3x^2/3-19x^1/3-40=0

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Solution for 3x^2/3-19x^1/3-40=0 equation: 


x in (-oo:+oo)

(3*x^2)/3-((19*x^1)/3)-40 = 0

(3*x^2)/3+(-19/3)*x-40 = 0

x^2-19/3*x-40 = 0

DELTA = (-19/3)^2-(-40*1*4)

DELTA = 1801/9

DELTA > 0

x = ((1801/9)^(1/2)+19/3)/(1*2) or x = (19/3-(1801/9)^(1/2))/(1*2)

x = ((1801/9)^(1/2)+19/3)/2 or x = (19/3-(1801/9)^(1/2))/2

x in { (19/3-(1801/9)^(1/2))/2, ((1801/9)^(1/2)+19/3)/2 }

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